Question

Решите способом подстановки и распишите ответ пожалуйста {6x+3=8x-3(2y-4) {2(2x-3y)-4x=2y-8

Answer 1

Смотри решение на фото

Answer 2

Solving the Equations by Substitution

To solve the system of equations given, we'll use the method of substitution. This involves solving one equation for one variable and then substituting that expression into the other equation. Let's solve the given system of equations step by step.

Step 1: Solve for y in the second equation

The second equation is: \[ 2(2x-3y)-4x=2y-8 \]

Let's solve for y: \[ 4x - 6y - 4x = 2y - 8 \] \[ -6y = 2y - 8 \] \[ -6y - 2y = -8 \] \[ -8y = -8 \] \[ y = 1 \]

So, we have found the value of y.

Step 2: Substitute y into the first equation

The first equation is: \[ 6x + 3 = 8x - 3(2y-4) \]

Substitute the value of y into the first equation: \[ 6x + 3 = 8x - 3(2*1-4) \] \[ 6x + 3 = 8x - 3(-2) \] \[ 6x + 3 = 8x + 6 \]

Step 3: Solve for x

Now, let's solve for x: \[ 3 = 8x - 6x + 6 \] \[ 3 = 2x + 6 \] \[ 2x = 3 - 6 \] \[ 2x = -3 \] \[ x = -\frac{3}{2} \]

So, the solution to the system of equations is: \[ x = -\frac{3}{2} \] \[ y = 1 \]

Therefore, the solution to the system of equations is x = -3/2 and y = 1.