Question

2с(1+с)-(с-2)(с+4) помогите пожалуста

Answer 1

Раскрываем скобки и приводим подобные слагаемые:
2c + 2c^2 - (c^2 + 4c - 2c - 8) = 2c + 2c^2 - c^2 - 4c + 2c + 8 = c^2 + 8 - это ответ.

Answer 2

Calculating the Expression

To solve the given expression, we can follow the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

The given expression is: 2c(1+c) - (c-2)(c+4)

Applying the Order of Operations

1. Simplify within the Parentheses: - 2c(1+c) simplifies to 2c + 2c^2 - (c-2)(c+4) simplifies to c^2 + 2c - 8

2. Substitute the Simplified Expressions: - 2c(1+c) - (c-2)(c+4) becomes 2c + 2c^2 - (c^2 + 2c - 8)

3. Combine Like Terms: - 2c + 2c^2 - (c^2 + 2c - 8) simplifies to 2c + 2c^2 - c^2 - 2c + 8 - This further simplifies to 2c^2 - c^2 + 2c - 2c + 8 - Finally, it becomes c^2 + 8

So, the simplified expression is c^2 + 8.

Conclusion

The value of the given expression 2c(1+c) - (c-2)(c+4) simplifies to c^2 + 8.