Question

Какие из пар чисел (-1;3),(-3;0),(0;4) являются решением уравнения 4x-3y+12=0

Answer 1

Имеем точку (-1; 3), где х=-1,  а  у=3
теперь проверим будет ли эта точка решением уравнения:
4*(-1)-3*3+12=-4-9+12=-13+12=-1,  должно быть 0, значит данная точке не есть решением

точка(-3; 0)
4*(-3)-3*0+12=-12-0+12=0
есть решением

точка(0; 4)
4*0-3*4+12=0-12+12=0
также есть решением уравнения

Answer 2

(-3:0)
4*(-3)-3*0+12=0

Answer 3

The equation 4x - 3y + 12 = 0 represents a linear equation in two variables, x and y. To determine which pairs of numbers (-1, 3), (-3, 0), and (0, 4) are solutions to this equation, we can substitute the values of x and y from each pair into the equation and check if the equation holds true.

Let's go through each pair of numbers and substitute them into the equation:

1. Pair (-1, 3): Substituting x = -1 and y = 3 into the equation: 4*(-1) - 3*(3) + 12 = -4 - 9 + 12 = -13 + 12 = -1 The equation does not hold true when we substitute (-1, 3) into it.

2. Pair (-3, 0): Substituting x = -3 and y = 0 into the equation: 4*(-3) - 3*(0) + 12 = -12 + 12 = 0 The equation holds true when we substitute (-3, 0) into it.

3. Pair (0, 4): Substituting x = 0 and y = 4 into the equation: 4*(0) - 3*(4) + 12 = 0 - 12 + 12 = 0 The equation holds true when we substitute (0, 4) into it.

Therefore, the pairs of numbers (-3, 0) and (0, 4) are solutions to the equation 4x - 3y + 12 = 0. The pair (-1, 3) is not a solution to the equation.