Question

Два туриста вышли одновременно из двух городов расстояние между которыми 38 км и встретились через 4 часа какой скорости шёл каждый турист если известно что первый прошел до встречи на 2 км больше второго

Answer 1

х км - прошёл1 турист (х+2)км прошёл 2 турист. х+х+2=38км => х=18 => 18/4 -это скорость одного а 20/4 - это скорость другого

Answer 2

Problem Analysis

Two tourists start simultaneously from two cities that are 38 km apart and meet after 4 hours. The first tourist has traveled 2 km more than the second tourist before they meet. We need to find the speed at which each tourist was traveling.

Solution

Let's assume the speed of the first tourist is x km/h and the speed of the second tourist is y km/h.

We know that the distance traveled by each tourist is equal to their speed multiplied by the time taken. Therefore, we can write the following equations:

For the first tourist: Distance = Speed * Time 38 km = x km/h * 4 hours

For the second tourist: Distance = Speed * Time 38 km = y km/h * 4 hours

We also know that the first tourist traveled 2 km more than the second tourist before they met. Therefore, we can write the following equation:

Distance traveled by the first tourist = Distance traveled by the second tourist + 2 km x km/h * 4 hours = y km/h * 4 hours + 2 km

Now we have a system of two equations with two variables. We can solve this system of equations to find the values of x and y.

Solution Steps

1. Solve the first equation for x: x = 38 km / 4 hours = 9.5 km/h. 2. Substitute the value of x in the second equation: 9.5 km/h * 4 hours = y km/h * 4 hours + 2 km. 3. Simplify the equation: 38 km = 4y km/h + 2 km. 4. Subtract 2 km from both sides: 36 km = 4y km/h. 5. Divide both sides by 4: 9 km = y km/h.

Therefore, the first tourist was traveling at a speed of 9.5 km/h, and the second tourist was traveling at a speed of 9 km/h.

Answer: The first tourist was traveling at a speed of 9.5 km/h, and the second tourist was traveling at a speed of 9 km/h.