Question

В коридоре детского сада стояли велосипеды двухколёсные и трёхколёсные когда посчитали рули их оказалось 7 а колёс 18 сколько двухколёсных и двухколёсных велосипедов.Составте уравнение .

Answer 1

пусть х - число двухколесных велосипедов , тогда  число

трехколесных  будет равно ( 7-х ) ,общее число колес равно 18 , составим уравнение :

2x +3·(7-x) = 18  ⇔  2x+21 -3x = 18  ⇔  x = 3  , 7-x = 4

ответ : двухколесных велосипедов -  3 , трехколесных - 4

Answer 2

Problem Analysis

We are given that there are a total of 7 bicycles and 18 wheels in the corridor of a kindergarten. We need to determine the number of two-wheeled and three-wheeled bicycles. We can solve this problem by setting up a system of equations.

Solution

Let's assume that the number of two-wheeled bicycles is represented by x, and the number of three-wheeled bicycles is represented by y.

We know that there are a total of 7 bicycles, so we can write the equation: x + y = 7 We also know that there are a total of 18 wheels, and each two-wheeled bicycle has 2 wheels, while each three-wheeled bicycle has 3 wheels. So we can write the equation: 2x + 3y = 18 Now we have a system of equations: x + y = 7 2x + 3y = 18

We can solve this system of equations to find the values of x and y.

To solve the system of equations, we can use the method of substitution or elimination. Let's use the method of substitution.

From the first equation, we can express x in terms of y: x = 7 - y

Substituting this value of x into the second equation, we get: 2(7 - y) + 3y = 18 Simplifying the equation: 14 - 2y + 3y = 18 Combining like terms: 14 + y = 18 Subtracting 14 from both sides: y = 4

Now that we have the value of y, we can substitute it back into the first equation to find the value of x: x + 4 = 7 Subtracting 4 from both sides: x = 3

Therefore, there are 3 two-wheeled bicycles and 4 three-wheeled bicycles in the corridor of the kindergarten.

Answer

There are 3 two-wheeled bicycles and 4 three-wheeled bicycles in the corridor of the kindergarten.