Question

X2+nx+6=0 нужно найти n. помогите пожалуйста срочно...

Answer 1

$x^2 + nx + 6 = 0\\D=b^2-4ac=n^2-4*6=n^2-24\\n^2-24=0\\(n-\sqrt{24})*(n+\sqrt{24})=0\\1)n-\sqrt{24}=0\\n=2\sqrt{6}\\2)n+\sqrt{24}=0\\n=-2\sqrt{6}$

Answer 2

I can help you with your math problem.

To find n, you need to solve the quadratic equation $x^2 + nx + 6 = 0$ for x. There are two methods to do this: using the quadratic formula or factoring.

Using the quadratic formula, you get:

$$x = \frac{-n \pm \sqrt{n^2 - 24}}{2}$$

Using factoring, you need to find two numbers that add up to n and multiply to 6. For example, if n = 5, then the two numbers are 2 and 3, and you can write:

$$x^2 + 5x + 6 = (x + 2)(x + 3)$$

Then you can solve for x by setting each factor to zero:

$$x + 2 = 0 \quad \text{or} \quad x + 3 = 0$$

$$x = -2 \quad \text{or} \quad x = -3$$

You can check your answer by plugging it back into the original equation.

For more help, you can visit [Mathway](https://www.mathway.com/ru/Algebra), a website that can solve algebra problems with step-by-step explanations. You can also see an example of a similar problem [here](https://online-otvet.ru/algebra/5cea9d2596f4e19a2952c524).

I hope this helps you with your homework. Have a nice day!