Question

Помогите решить уравнение, пожалуйста

Answer 1

$3\cdot (3^{\sqrt{x}+3})^{\frac{2}{\sqrt{x}+1}}=\frac{3}{\sqrt[10]{3}}\; ;\; \; \; ODZ:\; \; x \geq 0\\\\3^{1+\frac{2(\sqrt{x}+3)}{\sqrt{x}+1}}=3^{1-\frac{1}{10}}\\\\\frac{\sqrt{x}+1+2\sqrt{x}+6}{\sqrt{x}+1}=\frac{9}{10}\\\\30\sqrt{x}+70=9\sqrt{x}+9\\\\21\sqrt{x}=-61\\\\21\sqrt{x} \geq 0\; ,\; \; a\; \; \; -61\ \textless \ 0\; \; \Rightarrow \; \; net\; reshenij\\\\ Otvet:\; \; x\in \varnothing$

Answer 2

Solving an Equation

Sure, I can help you solve an equation. Could you please provide me with the equation you would like to solve?