Question

Ребят, помогите, пожалуйста

Answer 1

$A=10000a+1000b+100c+80+d, \\ d\in\{0, 2, 4, 6, 8\}, (a+b+c+8+d)\vdots3,\\ A_1=80000+1000a+100b+10c+d, \\ A_1-A = 799200+9000a+900b+90c = 69750, \\ 90(100a+10b+c)=10350, \\ 100a+10b+c=115, \\ a=1, b=1, c=5, \\ a+b+c+8+d=1+1+5+8+d=15+d, \\ \left [ {{d=0,} \atop {d=6;}} \right. \\ \left [ {{A=11580,} \atop {A=11586.}} \right.$