Question

(Корень 42-2)^2 Корень из 2^*3^6*5^2 (^-степень)

Answer 1

$(\sqrt{42}-2)^2=(\sqrt{42})^2-2*\sqrt{42}*2+2^2=\\\\42-4\sqrt{42}+4=46-4\sqrt{42}$
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$\sqrt{2^2*3^6*5^2}=2^{2:2}*3^{6:2}*5^{2:2}=\\\\2^1*3^3*5^1=2*5*27=10*27=270$