Question

4+xy+2(x+y)=0 как решить. даю 10 баллов. пожалуйста.

Answer 1

$4+xy+2(x+y)=0 \\ 4+xy+2x+2y=0;\\ 4+xy+2y+2x=0;\\ 4+y(x+2)+2x=0;\\ y(x+2)=-2x-4;\\ y=\frac{-2x-4}{x+2}=-\frac{2(x+2)}{x+2}=-2;$
у от х не зависит, сделаем то-же для х
$4+xy+2(x+y)=0 \\ 4+xy+2x+2y=0;\\ 4+x(y+2)+2y=0;\\ x(y+2)=-2y-4;\\ x=\frac{-2y-4}{y+2};\\ x=-2\frac{y+2}{y+2}=-2;$
имеем ответ:х=-2; y=-2.
можно проверить правильность ответа:
$4+(-2)\cdot(-2)+2(-2-2)=4+4+2\cdot(-4)=8-8=0.$

Answer 2

Solving the Equation 4xy + 2(x + y) = 0

To solve the equation 4xy + 2(x + y) = 0, we can follow these steps:

Step 1: Simplify the equation by distributing the 2 to (x + y): - 4xy + 2x + 2y = 0

Step 2: Group the terms with x and y: - (4xy + 2x) + 2y = 0

Step 3: Factor out the common terms: - 2x(2y + 1) + 2y = 0

Step 4: Combine like terms: - 4xy + 2x + 2y = 0

Step 5: Solve for x or y: - Let's solve for x in terms of y.

To do this, we can isolate the term with x by moving the other terms to the other side of the equation:

- 2x(2y + 1) = -2y - Divide both sides by 2(2y + 1): - x = -y / (2y + 1)

So, the solution to the equation 4xy + 2(x + y) = 0 is x = -y / (2y + 1).

Please note that this solution is derived based on the given equation. If you have any specific values for x or y, you can substitute them into the equation to find the corresponding solution.

I hope this helps! Let me know if you have any further questions.