Question

- 2x - 2xквадрат= -1 решите пожалуйста

Answer 1

Решение:
-2х -2х²=-1
-2х -2х²+1=0 Умножим на (-1)
2х²+2х-1=0
х1,2=(-2+-D)/2*2
D=√4-4*2*-1)=√(4+8)=√12=√(4*3)=2√3
х1=(-2+2√3)/4=2(-1+√3)/4=(-1+√3)/2=(√3-1)/2
х2=(-2-2√3)/4=2(-1-√3)/4=(-1-√3)/2

Ответ: х1=(√3-1)/2; х2=(-1-√3)/2

Answer 2

-2х-2х²=-1
 -2х-2х²+1=0
   -(2х²+2х-1)=0  левую и правую части уравнения умножим на  (-1)
  и тогда запишем 2х²+2х-1=0 решим квадратное уравнение 
      х1,2= (-1+/-√1+2)/2=(-1+/-√3)/2
         х1=(-1+√3)/2   х2=(-1-√3)/2
      
    

Answer 3

Equation: 2x + 2x^2 = -1

To solve the equation 2x + 2x^2 = -1, we need to find the values of x that satisfy the equation.

Solution:

To solve the equation, we can rearrange it into a quadratic equation by moving all the terms to one side:

2x^2 + 2x + 1 = 0

Now, we can use the quadratic formula to find the solutions for x:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 2, b = 2, and c = 1. Substituting these values into the quadratic formula, we get:

x = (-2 ± √(2^2 - 4 * 2 * 1)) / (2 * 2)

Simplifying further:

x = (-2 ± √(4 - 8)) / 4

x = (-2 ± √(-4)) / 4

Since the discriminant (√(4 - 8)) is negative, the equation has no real solutions. Therefore, there are no values of x that satisfy the equation 2x + 2x^2 = -1.

Answer: The equation 2x + 2x^2 = -1 has no real solutions.