Question

1) (2-b)(b+2)=4-b в квадрате2) -(b-2)(2-4b)=(2-b)(4b-3)3) (b+2)(3-2b)=6-b-4bв квадрате4) (b-4)В квадрате=bв квадрате -4b+16

Answer 1

формула сокращ умнож     4-б в квадрате =4-бв квадрате (и)

                                          2) (2-б)(2-4б)=(2-б)(4б-3)  ( л)

                                           3) -2б в кв. -б+6=6-б-4б в кв.  (Л)

                                    4) формул сокр умнож б в кв -8б +16= bв квадрате -4b+16( л)

Answer 2

1) To solve the equation (1)+(2-b)(b+2)=4-b+в^2, we start by simplifying the expression on the left side:

(2-b)(b+2) = 2(b+2) - b(b+2) = 2b + 4 - b^2 - 2b = -b^2 + 4

So the equation becomes:

1 + (-b^2 + 4) = 4 - b + в^2

Simplifying further:

1 - b^2 + 4 = 4 - b + в^2 5 - b^2 = 4 - b + в^2

Rearranging the terms:

b^2 - b + в^2 = 1

2) To solve the equation -(b-2)(2-4b)=(2-b)(4b-3), we start by expanding both sides of the equation:

-2(2-4b) + 4b(2-4b) = (2-b)(4b-3) -4 + 8b + 8b^2 = 8b^2 - 6b + 3

Simplifying further:

8b^2 - 16b - 8b^2 = 8b^2 - 6b + 3 -24b = -6b + 3

Rearranging the terms:

-18b = 3 b = -3/18 b = -1/6

3) To solve the equation (b+2)(3-2b)=6-b-4bв^2, we start by expanding both sides of the equation:

3(b+2) - 2b(b+2) = 6 - b - 4bв^2 3b + 6 - 2b^2 - 4b = 6 - b - 4bв^2

Simplifying further:

-2b^2 - b - 4b + 3b + 6 = 6 - b - 4bв^2 -2b^2 - 2b + 6 = 6 - b - 4bв^2

Rearranging the terms:

-2b^2 - 2b + b + 4bв^2 = 0 -2b^2 - b + 4bв^2 = 0

4) To solve the equation (b-4)в^2=bв^2 - 4b + 16, we start by expanding both sides of the equation:

bв^2 - 4в^2 = bв^2 - 4b + 16

Simplifying further:

-4в^2 + 4b - 16 = 0 4b - 4в^2 - 16 = 0

Rearranging the terms:

4b - 4в^2 = 16