Question

в одном пенале y карандашей а в другом - в 4 раза больше. в первый пенал добавили 5 карандашей,а из второго вынули 7 карандашей. карандашей в пеналах стало поровну.выясните,сколько карандашей было в первом пенале

Answer 1

4y-7=y+5, 3y=12, y=4,,,,,,,,,,,,,,,,,,,,,,,

Answer 2

Solution:

Let's solve this step by step.

1. Let's assume the number of pencils in the first pencil case is x and the number of pencils in the second pencil case is 4x.

2. After adding 5 pencils to the first case and removing 7 pencils from the second case, the number of pencils in both cases becomes equal.

3. We can create the following equation to represent this situation: - x + 5 = 4x - 7

4. Now, let's solve for x to find the number of pencils in the first case.

- x + 5 = 4x - 7 - 5 + 7 = 4x - x - 12 = 3x - x = 4

Answer:

The number of pencils in the first pencil case was 4.