Question

X В КВАДРАТЕ - 10Х +21 БОЛЬШЕ ИЛИ РАВНО 0

Answer 1

$x^{2} -10x+21 \geq 0$
$x^{2} -10x+21 = 0$
Находим Дискриминант (в вложений)
Ответ : 
$x_{1} = 3$
$x_{2} = 7$

Answer 2

Solving the Equation X in the Quadratic -10X + 21 ≥ 0

To solve the inequality -10X + 21 ≥ 0, we need to find the values of X that satisfy this inequality.

Step 1: Simplify the Inequality The first step is to simplify the given inequality.

The inequality is -10X + 21 ≥ 0.

Step 2: Solve for X To solve for X, we can use the following steps:

-10X + 21 ≥ 0 -10X ≥ -21 X ≤ -21 / -10 X ≤ 2.1

Therefore, the solution to the inequality -10X + 21 ≥ 0 is X ≤ 2.1.

This means that any value of X less than or equal to 2.1 will satisfy the given inequality.