Question

В ящике лежат 7желтых и15 зеленых найдите вероятность того что первым возьмут зеленый шар вторым желтый

Answer 1

0,7- вероятность того, что первым возьмут зелёный шар
0,3 - вероятность того, что вторым возьмут жёлтый шар

Answer 2

Вероятность в том, что зеленых шаров в 2 раза больше, а значит вероятность того, что их возьмут первыми в 2 раза больше чем желтые. 

Answer 3

Calculating the Probability of Drawing a Green Ball First and a Yellow Ball Second

To calculate the probability of drawing a green ball first and a yellow ball second from a box containing 7 yellow balls and 15 green balls, we can use the formula for calculating the probability of two independent events.

The formula for the probability of two independent events is given by: $$ P = \frac{C_{\text{green}}^1 \cdot C_{\text{yellow}}^1}{C_{\text{total}}^2} $$

Where: - $C_{\text{green}}^1$ is the number of ways to choose 1 green ball - $C_{\text{yellow}}^1$ is the number of ways to choose 1 yellow ball - $C_{\text{total}}^2$ is the number of ways to choose 2 balls from the total number of balls

Using the given numbers, we can calculate the probability.

The number of ways to choose 1 green ball from 15 green balls is 15, and the number of ways to choose 1 yellow ball from 7 yellow balls is 7. The total number of ways to choose 2 balls from 22 balls is given by the combination formula $C_{22}^2 = \frac{22!}{2!(22-2)!} = 231$.

Plugging these values into the formula, we get: $$ P = \frac{15 \cdot 7}{231} = \frac{105}{231} \approx 0.454 $$

So, the probability of first drawing a green ball and then a yellow ball is approximately 0.454.