Question

(10X-4)(3X+2)=0 я не знаю если можно то с объяснением

Answer 1

(10X-4)(3X+2)=0
30х²+20х-12х-8=0
30х²+8х-8=0
a=30, b=8, c= -8
D=b²-4ас=8²-4*30*(-8)=64+960=1024
х1= $\frac{-b- \sqrt{D} }{2a} = \frac{-8- \sqrt{1024} }{2*30} = \frac{-40}{60} = - \frac{2}{3}$
x2= $\frac{-b+ \sqrt{D} }{2a} = \frac{-8+ \sqrt{1024} }{2*30} = \frac{24}{60} = \frac{3}{5}$
Ответ: - $\frac{2}{3} ; \frac{3}{5}$

Answer 2

Solving the Equation (10X-4)(3X+2)=0

To solve the equation (10X-4)(3X+2)=0, we can use the zero product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be zero.

So, we can set each factor equal to zero and solve for X:

1. Set 10X-4 = 0 and solve for X: - 10X - 4 = 0 - 10X = 4 - X = 4/10 - X = 0.4.

2. Set 3X+2 = 0 and solve for X: - 3X + 2 = 0 - 3X = -2 - X = -2/3 - X = -0.67.

Therefore, the solutions to the equation (10X-4)(3X+2)=0 are X = 0.4 and X = -0.67.

This means that when X is equal to 0.4 or -0.67, the equation (10X-4)(3X+2) equals zero.

I hope this helps! If you have any further questions, feel free to ask.