Question

(у^2+2у-3)-(у^2-3у+4)=у-1

Answer 1

(y² +2y-3)-(y²-3y+4)=y-1
y²+2y-3-y²+3y-4=y-1
5y-7=y-1
5y-y=-1+7
4y=6
y=1.5
Ответ: 1,5

Answer 2

I can help you with your math problem. Here is the detailed solution:

(у^2+2у-3)-(у^2-3у+4)=у-1

To solve this equation, we need to simplify the left side by subtracting the terms with the same power of у. We get:

(у^2-у^2)+(2у-(-3у))+(-3-4)=у-1

Simplifying further, we get:

5у-7=у-1

Next, we need to isolate у on one side by subtracting у from both sides. We get:

4у-7=-1

Then, we add 7 to both sides to get rid of the constant term on the left side. We get:

4у=6

Finally, we divide both sides by 4 to get the value of у. We get:

у=6/4

Simplifying the fraction, we get:

у=3/2

Therefore, the solution of the equation is у=3/2.Ответь+подробно.+(у^2+2у-3)-(у^2-3у+4)=у-1