Question

Изобразите на координатной плоскости первые пять членов арифметической прогрессии 1;4;7... напишите уравнение прямой на которой лежат эти точки

Answer 1

Ответ ответ ответ ответ ответ

Answer 2

Первые 5 членов: 1; 4; 7; 10;13. Все лежат на оси ОХ. Уравнение оси y=0.

Answer 3

Arithmetical Progression and Graph Plotting

The first five terms of the arithmetic progression 1, 4, 7... can be calculated by adding 3 to each previous term. Therefore, the first five terms are: 1. 1 2. 4 3. 7 4. 10 5. 13

Let's plot these points on the coordinate plane and find the equation of the line that passes through these points.

The equation of an arithmetic progression is given by: a_n = a_1 + (n-1)d where: - a_n is the nth term - a_1 is the first term - d is the common difference - n is the term number

For the given arithmetic progression, the first term (a_1) is 1 and the common difference (d) is 3.

Graph Plotting

Now, let's plot the first five terms of the arithmetic progression on the coordinate plane.

| Term (n) | Value (a_n) | |----------|-------------| | 1 | 1 | | 2 | 4 | | 3 | 7 | | 4 | 10 | | 5 | 13 |

Equation of the Line

The equation of the line passing through these points can be found using the point-slope form of a line: y - y1 = m(x - x1) where: - (x1, y1) is a point on the line - m is the slope of the line

The slope (m) can be calculated using the first and fifth points: m = (y2 - y1) / (x2 - x1)

Substituting the values: m = (13 - 1) / (5 - 1) = 3

Using the first point (1, 1): y - 1 = 3(x - 1)

Therefore, the equation of the line is: y = 3x - 2