Question

Решите уравнение:а) (2х – 5)2 – (2х – 3)(2х + 3) = 0; б) 9у2 – 25 = 0.

Answer 1

a) (2x-5)2-(2x-3)(2x+3)=0

4x-10-4x^2+9=0

4x^2-4x+1=0

(2x-1)^2=0

x=+- 1/2

 

b)так понимаю это y^2

 9y^2=25

y^2=25/9

y=+-5/3

Answer 2

Б) 9у=25+2

     9у=27

     у=27:9

     у=3

 

 

 

 

 

 

 

Answer 3

I can help you solve equations. Here is the detailed solution for your question:

а) (2x – 5)^2 – (2x – 3)(2x + 3) = 0

To solve this equation, we can use the method of completing the square. First, we expand the brackets and simplify the terms:

4x^2 - 20x + 25 - 4x^2 + 6x - 9 = 0

-14x + 16 = 0

Next, we move the constant term to the right side and divide both sides by the coefficient of x:

x = -16/-14

x = 8/7

This is the only solution for this equation, since it has a double root.

б) 9y^2 – 25 = 0

To solve this equation, we can use the method of factoring. We can rewrite the equation as a difference of squares:

(3y + 5)(3y - 5) = 0

Then, we can use the zero product property to find the solutions:

3y + 5 = 0 or 3y - 5 = 0

y = -5/3 or y = 5/3

These are the two solutions for this equation.

I hope this helps you understand how to solve equations. If you have any other questions, feel free to ask me.