Question

7x² +20x –12 = –x Помогите решить, пожалуйста

Answer 1

7х²+20х-12=-х
7х²+21х-12=0
D=b²-4ac=21²-4×7×(-12)=489
х¹,²=(-21+\-√489)\14

Answer 2

7x² + x + 20x - 12 = 0
7x² + 21x - 12 = 0
D = b² - 4ac = 441 - 28×(-12) = 777
x1,2 =( - 21 +/- √777)/14

Answer 3

Problem Statement

You are looking to solve the equation 7x² + 20x - 12 = -x. Let's go through the steps to find the solution.

Solution

To solve the equation 7x² + 20x - 12 = -x, we need to simplify and rearrange the equation to isolate the variable x.

Step 1: Move all the terms to one side of the equation: 7x² + 20x - 12 + x = 0

Step 2: Combine like terms: 7x² + 21x - 12 = 0

Now, we have a quadratic equation in the form ax² + bx + c = 0, where a = 7, b = 21, and c = -12.

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the values of a, b, and c into the quadratic formula, we get:

x = (-21 ± √(21² - 4 * 7 * -12)) / (2 * 7)

Simplifying further:

x = (-21 ± √(441 + 336)) / 14

x = (-21 ± √777) / 14

Now, we have two possible solutions for x:

x₁ = (-21 + √777) / 14

**x₂ = (-21 - √