Question

Раскрыть скобки (2x-4) все во 2 степени (2x+y^3)^ вся скобка еще во 2 степени

Answer 1

=4х²-16х +16

= 4х² + 4ху³ + у^6

Answer 2

1) (2x-4)²=2²x²-2*2x*4+4²=
=4x²-16x+16

2) (2x+y^3)²=2²x²+4xy^3+
+y^(3*2)=4x²+4xy^3+y^6

Answer 3

(2x-4)^2 = (2x-4)(2x-4) = 4x^2 - 8x - 8x + 16 = 4x^2 - 16x + 16

(2x+y^3)^2 = (2x+y^3)(2x+y^3) = 4x^2 + 2xy^3 + 2xy^3 + y^6 = 4x^2 + 4xy^3 + y^6

So, when we square both (2x-4) and (2x+y^3) and then multiply the results together, we get:

(4x^2 - 16x + 16)(4x^2 + 4xy^3 + y^6) = 16x^4 + 16x^3y^3 - 64x^3 + 16x^2y^3 - 64x^2 + 64xy^3 + 16x^3y^3 + 16x^2y^6 - 64xy^3 + 16xy^6 + 16y^6

So, the result of squaring both (2x-4) and (2x+y^3) and multiplying the results together is:

16x^4 + 32x^3y^3 + 16x^2y^6 - 128x^3 + 32xy^6 - 128x^2 + 128xy^3 + 16y^6