Question

(3-2x)^2=(2x-3)(1-6x) Решите срочно

Answer 1

(3-2x)^2=(2x-3)(1-6x)
9-12x+4x2=2x-12x2-3+18x
16x2-32x+12=0
4x2-8x+3=0
x12=(8+-корень(64-48))/8=(8+-4)/8= 1/2 3/2
x=1/2
x=3/2

Answer 2

9-6x-2x=2x-12x^2-3+18x
9-6x-2x-2x+12x^2+3-18x=0
12x^2-26x+12=0
D=100
x1=1.5
x2=0.6
Может быть так точно не знаю но вроде правельно!

Answer 3

Solving the Equation (3-2x)^2 = (2x-3)(1-6x)

To solve the equation (3-2x)^2 = (2x-3)(1-6x), we can start by expanding and simplifying the equation.

Expanding the left-hand side: (3-2x)^2 = (3-2x)(3-2x) = 9 - 6x - 6x + 4x^2 = 9 - 12x + 4x^2

Expanding the right-hand side: (2x-3)(1-6x) = 2x - 6x^2 - 3 + 18x = -3 + 20x - 6x^2

Now, we have the equation: 9 - 12x + 4x^2 = -3 + 20x - 6x^2

Simplify the equation by moving all terms to one side: 4x^2 + 6x^2 - 20x + 12x + 9 + 3 = 0 10x^2 - 8x + 12 = 0

We now have a quadratic equation in the form ax^2 + bx + c = 0. We can solve for x using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a)

Where a = 10, b = -8, and c = 12.

Calculating the discriminant: Δ = b^2 - 4ac = (-8)^2 - 4*10*12 = 64 - 480 = -416

Since the discriminant is negative, the equation has no real solutions. Therefore, the equation (3-2x)^2 = (2x-3)(1-6x) has no real solutions.

Conclusion: The equation (3-2x)^2 = (2x-3)(1-6x) has no real solutions.