Question

2.сократите дробь: 1) x^2-4 2) 5x-x^2 3)a^2-2a+1 ----------- -------------- --------------- x^2-5x+6 x^2+x-30 2a^2-3a+1

Answer 1

1)(x²-4)/(x²-5x+6)=(x+2)(x-2)/(x-2)(x-3)=(x+2)/(x-3), x≠2,x≠3
2)(5x-x²)/(x²+x-30)=x(5-x)/(x+6)(x-5)=-x/(x+6), x≠-6,x≠5
3)(a²-2a+1)/(2a²-3a+1)=(a-1)(a-1)/(a-1)(a+0,5)=(a-1)/(a+0,5), a≠1,a≠-0,5

Answer 2

Simplifying the Fraction

To simplify the fraction (x^2-4)/(5x-x^2+3+a^2-2a+1)/(x^2-5x+6+x^2+x-30+2a^2-3a+1), we can follow these steps:

1. Factorize the numerator and denominator. 2. Cancel out any common factors. 3. Simplify the resulting expression.

Let's apply these steps to the given fraction:

1. Factorize the numerator and denominator: - Numerator: (x^2-4) can be factored as (x+2)(x-2). - Denominator: (5x-x^2+3+a^2-2a+1)/(x^2-5x+6+x^2+x-30+2a^2-3a+1) cannot be further factored.

2. Cancel out any common factors: - There are no common factors between the numerator and denominator.

3. Simplify the resulting expression: - The simplified expression is (x+2)(x-2)/(5x-x^2+3+a^2-2a+1)/(x^2-5x+6+x^2+x-30+2a^2-3a+1).

Please note that the given expression is quite complex and cannot be further simplified without specific values for the variables involved.

I hope this helps! Let me know if you have any further questions.