Question

на рисунке изображен график функции y=x^2+3x. используя график,решите неравенство x^2+3xбольше равно 0

Answer 1

Рисунка нет( -построю сам.

Объяснение:

 x^2+3x>=0  - это можно записать как два графика и построить их в одной системе еоординат:

1.y=x^2+3x

2.y=0 -это прямая ,совпадающая с осью абсцисс.

И решение буут те промежутки когда первый график будет "выше" или "на" втором графике.

Ответ:x=(-<><>;-3]U[0;+<><>)

Answer 2

Solving the Inequality Using the Graph of y = x^2 + 3x

To solve the inequality x^2 + 3x ≥ 0 using the graph of the function y = x^2 + 3x, we can look at the points where the graph of the function crosses the x-axis. These points will help us identify the intervals where the inequality is satisfied.

The graph of the function y = x^2 + 3x crosses the x-axis at the points where y = 0. By analyzing the graph, we can determine the intervals where x^2 + 3x is greater than or equal to 0.

The graph shows that the function crosses the x-axis at x = 0 and x = -3. This means that the inequality x^2 + 3x ≥ 0 is satisfied for the intervals where x ≤ -3 and x ≥ 0.

Therefore, the solution to the inequality x^2 + 3x ≥ 0 is x ≤ -3 or x ≥ 0.

This conclusion is drawn from the analysis of the graph of the function y = x^2 + 3x, which shows the points where the function is greater than or equal to 0