Question

2x+3y=7 x-y =1 решите систему уравнений

Answer 1

2(1+у)+3у=7
2+2у+3у=7
2+5у=7
5у=7-2
5у=5
у=5:5
у=1
Значит х-1=1
х=1+1
х=2

Answer 2

Solving the System of Equations

To solve the system of equations 2x + 3y = 7 and x - y = 1, we can use various methods such as substitution, elimination, or matrix methods. Let's solve it using the substitution method.

We have the following equations: Equation 1: 2x + 3y = 7 Equation 2: x - y = 1

From Equation 2, we can express x in terms of y as follows: x = y + 1

Substituting this value of x into Equation 1, we get: 2(y + 1) + 3y = 7

Simplifying the equation, we have: 2y + 2 + 3y = 7 5y + 2 = 7 5y = 7 - 2 5y = 5 y = 1

Now, substituting the value of y back into Equation 2, we can find the value of x: x - 1 = 1 x = 1 + 1 x = 2

Therefore, the solution to the system of equations 2x + 3y = 7 and x - y = 1 is x = 2 and y = 1.

Solution:

x = 2 y = 1