Question

Х(х+2)(х-1)(х+1)=120 ПОМОГИТЕ РЕШИТЬ!!!

Answer 1

X(x+1)(x+2)(x+3)=120
x^4+6x^3+11x^2+6x-120=0
Разложим на множители x^4+6x^3+11x^2+6x-120:
(x-2)*(x+5)*(x^2+3x+12)=0

x-2=0
x1=2

x+5=0
x2=-5

x^2+3x+12=0
D=3^2-4*1*12=-39
Дискриминант меньше 0, нет корней.

Answer 2

Solving the Equation (х+2)(х-1)(х+1)=120

To solve the equation (х+2)(х-1)(х+1)=120, we can expand the equation and set it equal to zero. Then, we can solve for the values of x that satisfy the equation.

Expanding the equation, we get:

(х+2)(х-1)(х+1) - 120 = 0

Now, let's solve for x.

Factoring the Equation

To solve the equation, we can factor it. Factoring the equation gives us:

(х+2)(х-1)(х+1) - 120 = 0

(x^2 + x - 2)(x + 1) - 120 = 0

(x^3 + 2x^2 - x - 2)(x + 1) - 120 = 0

Now, we can set each factor equal to zero and solve for x.

Setting the first factor equal to zero:

x^3 + 2x^2 - x - 2 = 0

Solving for x

Unfortunately, the equation x^3 + 2x^2 - x - 2 = 0 does not have a simple solution. It requires more advanced techniques, such as factoring by grouping or using the rational root theorem, to find the exact solutions.

However, we can use numerical methods or a graphing calculator to approximate the solutions.

Please note that the exact solutions may not be easily obtainable without further simplification or using numerical methods.

Let me know if you need any further assistance!