
Один рабочий работал 7 ч, а другой - 5 ч.один рабочий работал 7 ч, а другой - 5 ч. всего они
изготовили 76 деталей. сколько деталей в час изготавливал каждый рабочий, если известно, что первый за час делал на 4 детали больше, чем второй?ПОЖАЛУЙСТА ОЧЕНЬ НУЖНО РЕШИТЬ СИСТЕМОЙ УРАВНЕНИЙ!!!!

Ответы на вопрос




Problem Analysis
We have two workers who worked for different hours and together they produced a total of 76 parts. We need to find out how many parts each worker produced per hour, given that the first worker produced 4 more parts per hour than the second worker.
Solution
Let's assume that the first worker produced x parts per hour, and the second worker produced y parts per hour.
From the given information, we can form two equations:
Equation 1: The first worker worked for 7 hours and produced a total of 76 parts. Equation 2: The second worker worked for 5 hours and produced a total of 76 parts.
Using these equations, we can solve for x and y.
Equation 1:
The first worker worked for 7 hours and produced a total of 76 parts. So, the equation can be written as: 7x = 76Equation 2:
The second worker worked for 5 hours and produced a total of 76 parts. So, the equation can be written as: 5y = 76Now, we need to find the values of x and y.
Solving the Equations
Let's solve Equation 1 for x: 7x = 76 Dividing both sides by 7: x = 76/7
Let's solve Equation 2 for y: 5y = 76 Dividing both sides by 5: y = 76/5
So, the first worker produced 76/7 parts per hour, and the second worker produced 76/5 parts per hour.
Calculation
Let's calculate the values:
The first worker produced 76/7 parts per hour, which is approximately 10.857 parts per hour.
The second worker produced 76/5 parts per hour, which is approximately 15.2 parts per hour.
Therefore, the first worker produced approximately 10.857 parts per hour, and the second worker produced approximately 15.2 parts per hour.
Answer
The first worker produced approximately 10.857 parts per hour, and the second worker produced approximately 15.2 parts per hour.
Please note that the values are approximate due to rounding.
Let me know if there's anything else I can help you with!


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