Question

Из двух городов, расстояние между которыми 300 км, вышли одновременно навстречу друг другу два поезда. Через 2 ч расстояние между ними было 80 км. Найдите скорость каждого поезда, если скорость одного из них на 10 км\ч меньше скорости другого.

Answer 1

1)300-80=220 км проехали поезда за два часа; 2)2х+2(х+10)=220; 4х+20=220; 4х=220-20; Х=200:4; Х=50 км/ч скорость одного поезда; 3)50+10=60 км/ч скорость второго поезда

Answer 2

Problem Analysis

We are given that two trains start simultaneously from two cities that are 300 km apart and are moving towards each other. After 2 hours, the distance between the trains is 80 km. We need to find the speed of each train, given that the speed of one train is 10 km/h less than the speed of the other train.

Solution

Let's assume the speed of the slower train is x km/h. Therefore, the speed of the faster train will be (x + 10) km/h.

We can use the formula distance = speed × time to solve this problem.

After 2 hours, the slower train will have traveled a distance of 2x km and the faster train will have traveled a distance of 2(x + 10) km.

According to the problem, the sum of the distances traveled by both trains is equal to the total distance between the cities, which is 300 km. Therefore, we can write the equation:

2x + 2(x + 10) = 300

Simplifying the equation:

2x + 2x + 20 = 300

4x + 20 = 300

4x = 280

x = 70

Therefore, the speed of the slower train is 70 km/h and the speed of the faster train is 80 km/h.

Answer

The speed of the slower train is 70 km/h and the speed of the faster train is 80 km/h.