Question

1. x+z=5 x-3z=0 2. 2p+q=11 5p-2q=41 ПОМОГИТЕ РЕШИТЬ СИСТЕМЫ

Answer 1

Применено решение системы способом сложения

Answer 2

1.
x+z=5
x-3z=0
Умножаем первое уравнение на 3
3х+3z=15
x-3z=0
Складываем
4х=15
х=15/4=3,75
z=5-x=5-3,75=1,25
О т в е т. x=3,75; z=1,25.
2.
2p+q=11
5p-2q=41
Умножаем первое уравнение на 2
4p+2q=22
5p-2q=41
Складываем
9p=63
p=7
q=11-2p=11-14=-3
О т в е т. p=7; q=-3

Answer 3

System of Equations

To solve the system of equations:

1. x + z = 5 2. x - 3z = 0

We can use various methods such as substitution, elimination, or matrices. Let's solve it using the substitution method.

Substitution Method

We can solve the first equation for x and substitute it into the second equation:

From equation 1, we have x = 5 - z.

Substituting this value of x into equation 2, we get:

(5 - z) - 3z = 0

Simplifying the equation:

5 - z - 3z = 0

5 - 4z = 0

Now, let's solve for z:

-4z = -5

z = -5 / -4

z = 5/4 or 1.25

Substituting the value of z back into equation 1, we can find x:

x + 1.25 = 5

x = 5 - 1.25

x = 3.75

Therefore, the solution to the system of equations is x = 3.75 and z = 1.25.