Question

4x^2-x-4=0 Pomogite!

Answer 1

D=1+48=49=7^2
x1=(1+7)/8=1
x2=(1-7)/8= -3/4

Answer 2

Solving the Equation 4x^2 - x - 4 = 0

To solve the equation 4x^2 - x - 4 = 0, we can use the quadratic formula. The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 4, b = -1, and c = -4. Plugging these values into the quadratic formula, we get:

x = (-(-1) ± √((-1)^2 - 4(4)(-4))) / (2(4))

Simplifying further:

x = (1 ± √(1 + 64)) / 8

x = (1 ± √65) / 8

Therefore, the solutions to the equation 4x^2 - x - 4 = 0 are:

x = (1 + √65) / 8 and x = (1 - √65) / 8.

Please note that the exact values of the solutions depend on the context in which the equation is being solved. If you need a numerical approximation, you can calculate the decimal values using a calculator or software.

Let me know if there's anything else I can help you with!