Question

1)16х2+24х+9=0 2)2х2+7х-4=0 помогите решить пожалуйста

Answer 1

1)16x²+24x+9=0

D=576-4*16*9=0

x=-24/32=-0.75

 

2)2x²+7x-4=0

D=49-4*2*(-4)=49+32=81

x1=(-7+9)/4=0.5 x2=(-7-9)/4=-4

 

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Answer 2

1)16х2+24х+9=0

Д=24^2-4*9*16=576-576=0

х=-(24)/2*16=-0,75

 

2)2х2+7х-4=0

Д=7^2-4*2*(-4)=49+32=81

х1=-7-9/4=-4

х2=-7+9/4=0,5

Answer 3

Solving the Equations

To solve the given equations, let's use the quadratic formula. The quadratic formula is used to find the solutions of a quadratic equation of the form ax^2 + bx + c = 0, where a, b, and c are constants.

1) 16x^2 + 24x + 9 = 0: - Comparing this equation with the standard form ax^2 + bx + c = 0, we have a = 16, b = 24, and c = 9. - Applying the quadratic formula, the solutions for this equation are given by: ``` x = (-b ± √(b^2 - 4ac)) / (2a) ``` - Plugging in the values, we get: ``` x = (-24 ± √(24^2 - 4 * 16 * 9)) / (2 * 16) ``` - Simplifying further: ``` x = (-24 ± √(576 - 576)) / 32 x = (-24 ± √0) / 32 x = -24 / 32 x = -3 / 4 ``` - Therefore, the solution to the equation 16x^2 + 24x + 9 = 0 is x = -3/4.

2) 2x^2 + 7x - 4 = 0: - Comparing this equation with the standard form ax^2 + bx + c = 0, we have a = 2, b = 7, and c = -4. - Applying the quadratic formula, the solutions for this equation are given by: ``` x = (-b ± √(b^2 - 4ac)) / (2a) ``` - Plugging in the values, we get: ``` x = (-7 ± √(7^2 - 4 * 2 * -4)) / (2 * 2) ``` - Simplifying further: ``` x = (-7 ± √(49 + 32)) / 4 x = (-7 ± √81) / 4 x = (-7 ± 9) / 4 ``` - We get two possible solutions: - For x = (-7 + 9) / 4, we have x = 2 / 4 = 1/2. - For x = (-7 - 9) / 4, we have x = -16 / 4 = -4. - Therefore, the solutions to the equation 2x^2 + 7x - 4 = 0 are x = 1/2 and x = -4.

I hope this helps! Let me know if you have any further questions.