Question

на середине перегона длиной 224 км поезд был задержан на 13 мин. Хотя машинист увеличил скорость поезда на 10 км/ч, в пункт назначения поезд прибыл с опозданием на 1 мин.с какой скоростью шел поезд после остановки?

Answer 1

32 км/ч Вроде, я не знаю решение у меня остались записи, я решал такое.

Answer 2

Да там 32 получается я тоже решала

Answer 3

Calculation of Train Speed

To determine the speed of the train after the stop, we need to calculate the initial speed of the train before the stop. We can use the formula:

Speed = Distance / Time

Given: - Distance of the journey = 224 km - Delay during the journey = 13 min - Increased speed of the train = 10 km/h

Let's calculate the initial speed of the train before the stop:

1. Convert the delay time from minutes to hours: - Delay time = 13 min = 13/60 hours = 0.2167 hours

2. Calculate the time taken for the journey without the delay: - Time = Distance / Speed - Time = 224 km / (Speed + 10 km/h)

3. Calculate the time taken for the journey with the delay: - Time with delay = Time + 0.2167 hours

4. Set up an equation using the time taken for the journey with and without the delay: - Time with delay = Time + 0.2167 hours

5. Solve the equation to find the initial speed of the train before the stop.

Let's calculate the speed of the train after the stop using the given information.