Question

(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)-0.125*3^64 Упростить

Answer 1

Домножить и разделить на 3^2-1. Тогда в числителе все посокращается по разности квадратов. Останется (3^64-1)/(3^2-1)-3^64/8=-1/8

Answer 2

Simplifying the Expression

To simplify the given expression, we can start by factoring it. The expression is: (3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)-0.125*3^64

Let's break it down step by step.

1. Factorization of the expression: - We can use the formula for the difference of squares to factorize the expression. - The formula for the difference of squares is: a^2 - b^2 = (a + b)(a - b).

Applying this formula to each pair of terms in the given expression: - (3^2+1) = (3+1)(3-1) - (3^4+1) = (3^2+1)(3^2-1) - (3^8+1) = (3^4+1)(3^4-1) - **(3^16+1)