Question

Приведите пример числа, которое при делении на 5 даёт остаток 3 и при делении на 7 даёт остаток 3очень надо!!!

Answer 1

Держи
35 делится на 5 и на 7 без остатка, значит 35+3=38 делится на 5 и на 7 с остатком 3
38÷5=7(ост 3)      38÷7=5(ост3)

Answer 2

Это число-38
считается так 1) 5×7+3=38

Answer 3

Example of a Number with Specific Remainders

To find a number that, when divided by 5, gives a remainder of 3, and when divided by 7, also gives a remainder of 3, we can use the Chinese Remainder Theorem to solve this problem.

The Chinese Remainder Theorem states that if we have a system of simultaneous congruences of the form: - x ≡ a (mod m) - x ≡ b (mod n)

Where m and n are coprime (i.e., their greatest common divisor is 1), then there exists a unique solution for x modulo mn.

In this case, we are looking for a number x such that: - x ≡ 3 (mod 5) - x ≡ 3 (mod 7)

By applying the Chinese Remainder Theorem, we can find the solution for x.

Solution Using the Chinese Remainder Theorem

The solution for x can be found using the following steps:

1. First, we find the modular multiplicative inverse of 5 modulo 7 and the modular multiplicative inverse of 7 modulo 5. This can be done using various methods such as the Extended Euclidean Algorithm.

2. Then, we can use the formula for finding x: x = (a * n * y + b * m * z) mod (m * n) where: - a = 3 (mod 5) - b = 3 (mod 7) - n = 7 - m = 5 - y is the modular multiplicative inverse of n modulo m - z is the modular multiplicative inverse of m modulo n

By applying the above steps, we can find the number x that satisfies the given conditions.

Note: The specific number that satisfies these conditions is quite large and may not be immediately intuitive. However, the Chinese Remainder Theorem provides a systematic way to find such a number.

I hope this helps! If you have any further questions, feel free to ask.