Question

2. Горят две свечи неодинаковой длины и разной толщины. Более длинная сгорает за 3.5 часа, а короткая за 5 часов. Через 2 часа одновременного горения длины свечей оказались равными. Во сколько раз одна свеча первоначально была длиннее другой?

Answer 1

3,5х и 5y 
2 часа свечи равны 
1,5х / 3у = 1
1,5х=3у
х=2у
3,5*2у/5у= дельта
у сокращается получаем
7/5 или 1.4

Answer 2

Problem Analysis

We are given two candles of different lengths and thicknesses. The longer candle burns for 3.5 hours, while the shorter candle burns for 5 hours. After 2 hours of simultaneous burning, the lengths of the candles become equal. We need to determine the initial length ratio between the two candles.

Solution

Let's assume the initial length of the longer candle is L and the initial length of the shorter candle is S.

We know that the longer candle burns for 3.5 hours and the shorter candle burns for 5 hours. After 2 hours of simultaneous burning, the lengths of the candles become equal.

To find the initial length ratio, we can set up the following equation:

L - (3.5/5) * L = S - (3.5/5) * S

Simplifying the equation, we get:

L - (7/10) * L = S - (7/10) * S

Combining like terms, we have:

(3/10) * L = (3/10) * S

Dividing both sides by (3/10), we get:

L = S

This means that the initial lengths of the two candles were equal.

Therefore, the initial length ratio between the two candles is 1:1.

Answer

The initial length ratio between the two candles was 1:1.