Question

2х-4х в квадрате =0 как решит уравнение по теореме виета?

Answer 1

2x-4x^2=0
2x(1-2x)=0
2x=0
x1=0
1-2x=0
-2x=-1
2x=1
x2=1/2=0,5

Answer 2

Solving the Equation Using Vieta's Theorem

To solve the equation 2x^2 - 4x = 0 using Vieta's theorem, we can first identify the coefficients of the quadratic equation. The general form of a quadratic equation is ax^2 + bx + c = 0, where a, b, and c are the coefficients. In this case, the coefficients are: - a = 2 - b = -4 - c = 0

Using Vieta's Theorem

Vieta's theorem states that for a quadratic equation ax^2 + bx + c = 0, the sum of the roots is -b/a and the product of the roots is c/a.

1. Sum of the roots: - The sum of the roots is given by -b/a. - In this case, -b/a = -(-4)/2 = 2.

2. Product of the roots: - The product of the roots is given by c/a. - In this case, c/a = 0/2 = 0.

Conclusion

From Vieta's theorem, we can conclude the following about the roots of the equation 2x^2 - 4x = 0: - The sum of the roots is 2. - The product of the roots is 0.

This information provides insight into the nature of the roots of the quadratic equation.

- Source: ' 2^2-4-6=0 (2 4 6 0) - -. [ !]' - Source: ' 2-4-21=0 - Uchi.ru'