Question

В коробке лежат 4 белых и З черных шара. Наугад вынимают два шара. Какова Вероятность того, что вынуты белый и черный шары.

Answer 1

Вероятность, что первый чёрный, а второй белый

3/7*4/6=12/42=6/21

Вероятность, что первый  белый, а второй чёрный

4/7*3/6=12/42=6/21

Вероятность извлечения белого и чёрного шаров

 6/21+6/21=12/21= 0,5714

Answer 2

Calculating the Probability of Drawing a White and a Black Ball

To calculate the probability of drawing a white and a black ball from the box, we need to consider the total number of balls and the number of white and black balls in the box.

Let's assume that the box contains 4 white balls and 3 black balls.

The probability of drawing a white ball on the first draw is 4/7 because there are 4 white balls out of a total of 7 balls in the box.

After the first draw, there are 6 balls left in the box, including 3 white balls and 3 black balls. The probability of drawing a black ball on the second draw is 3/6 because there are 3 black balls out of a total of 6 balls remaining in the box.

To calculate the probability of both events happening (drawing a white ball and then a black ball), we multiply the probabilities of each event:

Probability of drawing a white ball and then a black ball = (4/7) * (3/6) = 2/7.

Therefore, the probability of drawing a white and a black ball from the box is 2/7.