Question

2cos°+5sin90°-4tg180°=

Answer 1

2*1+5*1-4*0=7                это ответ                                                                                                 

Answer 2

2cos°+5sin90°-4tg180°=

First, let's find the values of cos°, sin90°, and tg180°:

cos° = 1 (cosine of any angle is 1) sin90° = 1 (sine of 90 degrees is 1) tg180° = 0 (tangent of 180 degrees is 0)

Now we can substitute these values into the equation:

2(1) + 5(1) - 4(0) = 2 + 5 - 0 = 7

So, the value of the expression 2cos°+5sin90°-4tg180° is 7.