Question

4a - ax- 4x - x²= помогите ​

Answer 1

Ответ:

не решаемо

Объяснение:

обьяснение: все переменные разные

Answer 2

Solving the Equation 4a - ax - 4x - x² = 0

To solve the equation 4a - ax - 4x - x² = 0, we can follow these steps:

1. Rearrange the equation to form a quadratic equation in terms of x. 2. Use the quadratic formula to find the solutions for x.

Rearranging the Equation

The given equation is 4a - ax - 4x - x² = 0. We can rearrange it to form a quadratic equation in terms of x: x² - (a + 4)x + 4a = 0

Using the Quadratic Formula

The solutions for x can be found using the quadratic formula: x = (-b ± √(b² - 4ac)) / (2a)

Where a = 1, b = -(a + 4), and c = 4a.

Let's calculate the solutions for x using the quadratic formula.

Calculating the Solutions for x

For the equation x² - (a + 4)x + 4a = 0: a = 1, b = -(a + 4), and c = 4a.

Using the quadratic formula: D = b² - 4ac x = (-b ± √D) / (2a)

D = (-(-(a + 4)))² - 4 * 1 * 4a = (a + 4)² - 16a = a² + 8a + 16 - 16a = a² - 8a + 16

The solutions for x are: x1 = (a + 4 + √(a² - 8a + 16)) / 2 x2 = (a + 4 - √(a² - 8a + 16)) / 2

Let's discuss the solutions further if needed.