Question

Упростите выражение √18(√6-√2)-3√12

Answer 1

$\sqrt{18}(\sqrt6-\sqrt2)-3\sqrt12\\3\sqrt2(\sqrt{3*2}-\sqrt2)-6\sqrt3\\6\sqrt3-6-6\sqrt3=-6$

Answer 2

I can help you with math problems. To simplify the expression, we need to use the following properties of square roots:

- $$\sqrt{ab}=\sqrt{a}\sqrt{b}$$ - $$\sqrt{a^2}=|a|$$

Using these properties, we can rewrite the expression as follows:

$$\sqrt{18(\sqrt{6}-\sqrt{2})}-3\sqrt{12}$$ $$=\sqrt{18}\sqrt{\sqrt{6}-\sqrt{2}}-3\sqrt{4}\sqrt{3}$$ $$=\sqrt{9}\sqrt{2}\sqrt{\sqrt{6}-\sqrt{2}}-3\cdot 2\sqrt{3}$$ $$=3\sqrt{2}\sqrt{\sqrt{6}-\sqrt{2}}-6\sqrt{3}$$

This is the simplest form of the expression.Ответь+подробно.+Упростите+выражение+√18(√6-√2)-3√12