Question

ПОМОГИТЕ!СДЕЛАЙТЕ С РЕШЕНИЕМ-ЛУЧШИЙ ОТВЕТ! Выполните действия: 1)(аⁿ-1)³ 2)(у ͫ +2)³ 3)(хⁿ+хⁿ⁻¹)³ 4)(аⁿ⁺¹-аⁿ)³ 5)(2bⁿ+с ͫ )³ 6)(2/3аⁿ-b ͫ )³

Answer 1

(a^n-1)³=a^(3n) - 3a^(2n)+3n-1

(y^m +2)³=y^(3m)+6y^(2m)+6y^m +8

(x^n +x^(n-1))³=x^(3n) + 3x^(2n) x^(n-1)+3x^n x^(n^2 - 2n+1) +x^(n³-3n²+3n-1)=x^(3n)+3x^(3n-1)+3x^(n^2-n+1)+x^(3n-3)

(a^(n+1) - a^n)³=a^(n³+3n²+3n+1) - 3a^(n²+2n+1) a^(2n) +3a^(n+1) a^n - a^(3n)=a^(n³+3n²+3n+1) - 3a^(n²+4n+1)+3a^(2n+1) - a^3n

(2b^n+c^m)³=8b^(3n)+6b^2n c^m+6b^n c^(2m)+c^(3m)

(2/3 a^n - b^n)³=8/27 a^(3n) - 4/3 a^(2n) b^n + 2a^n b^(2n) - b^(3n)

Answer 2

Mathematical Expressions

Sure, I can help with that! Let's break down each expression step by step.

1) (aⁿ-1)³: - The expression (aⁿ-1)³ can be expanded using the formula (a - b)³ = a³ - 3a²b + 3ab² - b³. - Therefore, (aⁿ-1)³ = a³ - 3a² + 3a - 1.

2) (u + ͫ + 2)³: - It seems there might be a typo in the expression "u + ͫ + 2" as it's not clear what the intended operation is. Could you please provide more information or clarify the expression?

3) (xⁿ + xⁿ⁻¹)³: - The expression (xⁿ + xⁿ⁻¹)³ can be expanded using the formula (a + b)³ = a³ + 3a²b + 3ab² + b³. - Therefore, (xⁿ + xⁿ⁻¹)³ = x³ⁿ + 3x²ⁿxⁿ⁻¹ + 3xⁿx²ⁿ⁻¹ + x³ⁿ⁻¹.

4) (aⁿ⁺¹ - aⁿ)³: - The expression (aⁿ⁺¹ - aⁿ)³ can be expanded using the formula (a - b)³ = a³ - 3a²b + 3ab² - b³. - Therefore, (aⁿ⁺¹ - aⁿ)³ = a³ⁿ⁺³ - 3a²ⁿ⁺² + 3aⁿ⁺¹ - a³ⁿ.

5) (2bⁿ + с + ͫ)³: - Similar to expression 2, it seems there might be a typo in the expression "с + ͫ" as it's not clear what the intended operation is. Could you please provide more information or clarify the expression?

6) (2/3aⁿ - b + ͫ)³: - Similar to expressions 2 and 5, it seems there might be a typo in the expression "b + ͫ" as it's not clear what the intended operation is. Could you please provide more information or clarify the expression?

Feel free to provide more details or clarify the expressions, and I'd be happy to help further!