Question

Решите пожалуйста систему уравнений.Методом подстановки {x^2-3=y {x+y=3

Answer 1

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Answer 2

System of Equations

To solve the system of equations using the method of substitution, we have the following equations:

Equation 1: x^2 - 3 = y Equation 2: x + y = 3 We can solve this system of equations by substituting Equation 2 into Equation 1.

Solution

Substituting Equation 2 into Equation 1, we get:

x^2 - 3 = 3 - x

Rearranging the equation, we have:

x^2 + x - 6 = 0

Now, we can solve this quadratic equation by factoring or using the quadratic formula. Factoring the equation, we have:

(x + 3)(x - 2) = 0

Setting each factor equal to zero, we get:

x + 3 = 0 --> x = -3 x - 2 = 0 --> x = 2

Now, we substitute these values of x back into Equation 2 to find the corresponding values of y.

For x = -3: -3 + y = 3 y = 6

For x = 2: 2 + y = 3 y = 1

Therefore, the solution to the system of equations is: x = -3, y = 6 x = 2, y = 1

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