Question

В первый день со склада было отпущено 20% имевшегося там картофеля. Во второй день – 180% от того количества картофеля, которое было отпущено в первый день. В третий день – оставшиеся 88 кг картофеля. Сколько килограммов картофеля было на складе первоначально?

Answer 1

Решение: 

Пусть всего было xx кг картофеля.

Тогда в 1 день отпустили 0.2x0.2x кг, во второй день 0.2x∗1.8=0.36x0.2x∗1.8=0.36x кг. Составим уравнение и решим его.

x=0.2x+0.36x+88⇒0.44x=88⇒x=200.x=0.2x+0.36x+88⇒0.44x=88⇒x=200.

Ответ 200.

Answer 2

Calculation of Initial Potato Quantity

To calculate the initial quantity of potatoes on the warehouse, we need to analyze the information provided.

According to the information given: - On the first day, 20% of the potatoes that were in the warehouse were released. - On the second day, 180% of the quantity released on the first day was released. - On the third day, there were 88 kg of potatoes left.

Let's assume the initial quantity of potatoes in the warehouse is represented by the variable "x" (in kg).

On the first day, 20% of "x" was released, which is equal to 0.2x.

On the second day, 180% of the quantity released on the first day was released. This means 180% of 0.2x, which can be calculated as 1.8 * 0.2x = 0.36x.

On the third day, there were 88 kg of potatoes left, so the equation becomes: x - (0.2x + 0.36x) = 88.

Simplifying the equation: x - 0.56x = 88, 0.44x = 88, x = 88 / 0.44, x = 200.

Therefore, the initial quantity of potatoes in the warehouse was 200 kg.