Question

Х+3у=4 2х-у=1 методом сложения пожалуйста

Answer 1

$+ \left \{ {{x+3y=4} \atop {2x-y=1 ( *3) }} \right.$

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(x+3y)+3(2x−y)=4+3⋅1
7x=7x=1
(1)+3y=4
y=1
Ответ:(1;1)

Answer 2

Solving the System of Equations Using the Method of Substitution

To solve the system of equations 3y = 4 and 2x - y = 1 using the method of substitution, we can solve one of the equations for one variable and then substitute that expression into the other equation.

1. Solve the second equation for y: 2x - y = 1 y = 2x - 1

2. Substitute the expression for y into the first equation: 3(2x - 1) = 4 6x - 3 = 4 6x = 7 x = 7/6

3. Substitute the value of x back into the expression for y: y = 2(7/6) - 1 y = 7/3 - 1 y = 7/3 - 3/3 y = 4/3

Solution

Therefore, the solution to the system of equations 3y = 4 and 2x - y = 1 is: x = 7/6 and y = 4/3.