Question

Выполните действия:1. (7x²–5x+3)–(7x²–5)=2. (3x+1)+(–3x²–3x+1)=3. (a+3b)+(3a–3b)=4. a⁴–5ab–b²–(a²+b²)=5. (x+y–z)–(x–y)+(x–y+z)=

Answer 1

1. 7x²–5x+3-7x²+5=8-5x
2.3x+1-3x²-3x+1=2-3x²
3.a+3b+3a-3b=4a
4.a⁴–5ab–b²–a²-b²=a⁴–5ab–a²-2b²
5.x+y–z-x+y+x-y+z=x+y

Answer 2

1. (7x²–5x+3)–(7x²–5) = 7x²–5x+3–7x²+5 = -5x+8

2. (3x+1)+(–3x²–3x+1) = 3x+1–3x²–3x+1 = -3x²-3x+3x+1+1 = -3x²+2

3. (a+3b)+(3a–3b) = a+3b+3a–3b = a+3a+3b–3b = 4a

4. a⁴–5ab–b²–(a²+b²) = a⁴–5ab–b²–a²–b² = a⁴–a²–5ab–b²–b² = a⁴–a²–6b²–5ab

5. (x+y–z)–(x–y)+(x–y+z) = x+y–z–x+y+x–y+z = x-x+y+y-y+z+z = z