Question

6(9-2x)+8>=70-20x 3-2(x+4)>=2x+3 6(9-2x)+8>=70-20x Помогите!!!!!!!!!!!!!!!!!!!

Answer 1

3-2х-8>=2х+3 -2х-2х>=8 -4х>=8 Х<=-2 (-бесконечности до -2] 54-12х+8>=70-20х 8х>=8 Х>=8 [8;+бесконечноти)

Answer 2

To solve the inequality 6(9-2x) + 8 >= 70 - 20x + 3 - 2(x+4) >= 2x + 3 + 6(9-2x) + 8 >= 70 - 20x, we will simplify and solve each part separately.

Simplifying the inequality:

Let's start by simplifying each side of the inequality.

On the left side: 6(9-2x) + 8 = 54 - 12x + 8 = 62 - 12x

On the right side: 70 - 20x + 3 - 2(x+4) = 70 - 20x + 3 - 2x - 8 = 65 - 22x

Now we have the simplified inequality: 62 - 12x >= 65 - 22x.

Solving the inequality:

To solve the inequality, we will isolate the variable x on one side of the inequality.

Let's start by moving the terms with x to one side: 62 - 12x + 22x >= 65

Combine like terms: 62 + 10x >= 65

Next, let's isolate the variable x by moving the constant term to the other side: 62 - 65 >= -10x

Simplify: -3 >= -10x

To isolate x, we need to divide both sides of the inequality by -10. However, when dividing by a negative number, the inequality sign needs to be flipped: -3/(-10) <= x

Simplify: 3/10 <= x

So the solution to the inequality is x >= 3/10.

Please note that this solution assumes that there are no restrictions on the variable x. If there are any additional conditions or constraints, please provide them for a more accurate solution.