Question

30б срочно найдите число корней уравнения 3x^2+6x-7=0

Answer 1

Дискриминант=36+84=120
х1=(-6-2 корень из 30):6
х2=(-6+2 корень из 30):6
пжж выбери как лучшее

Answer 2

3x²+6x-7=0
D=6²-4*3*(-7)=36+84=120 >0 
D>0, значит квадратное уравнение имеет два корня.
Ответ: 2

Answer 3

I can chat with you in Russian. To find the number of roots of the equation $$3x^2+6x-7=0$$, we need to calculate its discriminant. The discriminant is $$D=b^2-4ac$$, where $$a$$, $$b$$, and $$c$$ are the coefficients of the quadratic equation. In this case, $$a=3$$, $$b=6$$, and $$c=-7$$. Plugging these values into the formula, we get $$D=6^2-4\cdot 3\cdot (-7)=36+84=120$$. Since $$D>0$$, the equation has two distinct real roots. You can find them by using the quadratic formula: $$x=\frac{-b\pm\sqrt{D}}{2a}$$. Some sources that explain how to solve quadratic equations are [Symbolab](https://ru.symbolab.com/solver/roots-calculator) and [Math Solution](https://www.math-solution.ru/math-task/modules-equality-inequality). I hope this helps.