Question

Найти производную y=1/x^2-4x+5 Помогите, пожалуйста

Answer 1

Y' = -2/x³ - 4     /////////////////////////////////

Answer 2

$y= \frac{1}{x^2} -4x+5=x^{-2}-4x+5\\y'=-2x^{-3}-4=- \frac{2}{x^3} -4$

Answer 3

Derivative of y=1/x^2-4x+5

To find the derivative of the function y=1/x^2-4x+5, we can use the power rule and the sum/difference rule for derivatives. The power rule states that if f(x) = x^n, then f'(x) = nx^(n-1). The sum/difference rule states that if f(x) = g(x) ± h(x), then f'(x) = g'(x) ± h'(x).

The derivative of y=1/x^2-4x+5 can be calculated as follows:

Step 1: Find the derivative of each term separately using the power rule. - For the term 1/x^2, the derivative is -2/x^3. - For the term -4x, the derivative is -4. - For the constant term 5, the derivative is 0.

Step 2: Combine the derivatives of each term using the sum rule. - The derivative of y=1/x^2-4x+5 is y' = -2/x^3 - 4.

Therefore, the derivative of the function y=1/x^2-4x+5 is y' = -2/x^3 - 4.