Question

Помогите упростить выражение 1+(а+3)(b-2)+2а- 3b и найти его значение при а+√32.b=√2

Answer 1

1+(a+3)(b-2)+2a-3b
1+ab-2a+3b-6+2a-3b = ab - 5
√32 * √2 - 5 = √64 - 5 = 8 - 5 = 3  

Answer 2

I can help you with math problems. Here is how to simplify the expression and find its value:

To simplify the expression, we need to use the distributive property and combine like terms. We get:

$$1+(a+3)(b-2)+2a-3b$$ $$= 1+ab-2a+3b-6+2a-3b$$ $$= ab-5$$

To find the value of the expression when $a=\sqrt{32}$ and $b=\sqrt{2}$, we need to substitute these values into the expression and simplify. We get:

$$ab-5$$ $$=(\sqrt{32})(\sqrt{2})-5$$ $$=\sqrt{64}-5$$ $$=8-5$$ $$=3$$

Therefore, the simplified expression is $ab-5$ and its value when $a=\sqrt{32}$ and $b=\sqrt{2}$ is $3$. I hope this helps.Ответь+подробно.+Помогите+упростить+выражение+1+(а+3)(b-2)+2а-+3b+и+найти+его+значение+при+а+√32.b=√2