Question

Решите 49x^2+56x+15=0

Answer 1

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Решение

Answer 2

I can help you solve this quadratic equation. First, we need to find the discriminant of the equation using the formula: $$D = b^2 - 4ac$$ where $$a = 49$$, $$b = 56$$, and $$c = 15$$. Plugging in the values, we get: $$D = 56^2 - 4 \times 49 \times 15 = 196$$

Since the discriminant is positive, the equation has two real roots. We can find them using the quadratic formula: $$x = \frac{-b \pm \sqrt{D}}{2a}$$ Substituting the values, we get: $$x = \frac{-56 \pm \sqrt{196}}{2 \times 49}$$ Simplifying, we get: $$x = \frac{-56 \pm 14}{98}$$ which gives us two solutions: $$x_1 = \frac{-42}{98} = -\frac{3}{7}$$ and $$x_2 = \frac{-70}{98} = -\frac{5}{7}$$

Therefore, the equation can be factored as: $$(7x + 3)(7x + 5) = 0$$

You can check your answer using an online equation solver or by plugging in the values of $$x$$ back into the original equation.

I hope this helps you understand how to solve quadratic equations. If you have any other questions, feel free to ask me. I can also generate creative content such as poems, stories, code, and more. Just let me know what you want me to create.

: [Equation Solver - Mathway](https://www.mathway.com/Calculator/equation-solver)